這是本文件的舊版!


攔截HTML或JSP

許多人都會有在Struts中如何攔截過濾HTML或JSP的需求。使用者想連結至某一個網頁,並不一定會登入才連結。他可能會將有興趣的網頁直接存到我的最愛,下次就直接連過去了。假如他是處於session過期或沒登入的情況呢?也許這個網頁就無法正常顯示了。在Struts中該如何在存取某些網頁前,先做狀態的檢查呢?

透過Filter

web.xml

如果使用Struts範例中的設定,通常會將所有的URL請求讓struts2處理。在這我們可以增加一個DelegatingFilterProxy,會去過濾*.html的頁面,而DelegatingFilterProxy會使用我所實作的Filter。

	<filter>
		<filter-name>struts2</filter-name>
		<filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
	</filter>
	<filter>
		<filter-name>DelegatingFilterProxy</filter-name>
		<filter-class>org.tonylin.funny.web.DelegatingFilterProxy</filter-class>
	</filter>	
	<filter-mapping>
		<filter-name>struts2</filter-name>
		<url-pattern>*</url-pattern>
	</filter-mapping>
	<filter-mapping>
		<filter-name>DelegatingFilterProxy</filter-name>
		<url-pattern>*.html</url-pattern>
	</filter-mapping>	

DelegatingFilterProxy

根據我的範例,除了login.html的頁面都必須檢查session中是否有User登入的資料,如果沒有就會將頁面導向login.html。

public class DelegatingFilterProxy extends StrutsPrepareAndExecuteFilter {
	private Logger logger = LoggerFactory.getLogger(DelegatingFilterProxy.class);
	final static private List<String> IGNORE_SESSION_CHECKING_LIST = Arrays.asList("/login.html");
 
	@Override
	public void doFilter(ServletRequest req, ServletResponse res,
			FilterChain chain) throws IOException, ServletException {
		HttpServletRequest request = (HttpServletRequest)req;
		HttpServletResponse response = (HttpServletResponse)res;
 
		String servletPath = request.getServletPath();
		logger.debug("doFilter: {},{}", servletPath,
				IGNORE_SESSION_CHECKING_LIST.indexOf(servletPath));
 
 
		if( SessionUtil.getAttribute(request, SessionKeys.ACCOUNT) == null && IGNORE_SESSION_CHECKING_LIST.indexOf(servletPath) == -1 ){
			response.sendRedirect("login.html");
		} else {
			super.doFilter(req, res, chain);	
		}
	}
 
 
}

友藏內心獨白: 下次會透過interceptor試看看!